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A beaker of 450g of water is heated from 4.0°C to 25.0°C on a hot plate. If the
specific heat of H2O is 4.18J/9°C how much energy has the water absorbed?
A 39,501 J

B 4.42 x 104

C 5.13 J

D 54,549 J

Respuesta :

Answer: 5.13

Explanation: juss do it

Taking into account the definition of calorimetry, the water has absorbed 39,501 J.

Calorimetry

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).

So, the equation that allows to calculate heat exchanges is:

Q = c× m× ΔT

where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

Energy that the water absorbed

In this case, you know:

  • Q= ?
  • c= 4.18 [tex]\frac{J}{gC}[/tex]
  • m= 450 g
  • ΔT= Tfinal - Tinitial= 25 C - 4 C= 21 C

Replacing in the definition of calorimetry:

Q = 4.18 [tex]\frac{J}{gC}[/tex]× 450 g× 21 C

Solving:

Q= 39,501 J

Finally, the water has absorbed 39,501 J.

Learn more about calorimetry:

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