Answer:
T = 486.6 K
Explanation:
The final temperature of the block can be found using the following formula:
[tex]Q = mC\Delta T\\[/tex]
where,
Q = Thermal Energy Transferred = 3.35 x 10⁵ J
m = mass of aluminum block = 2 kg
C = Specific Heat = 897 J/kg.K
ΔT = Change in Temperature = T - 300 K
T = Final Temperature of the Block = ?
Therefore,
[tex]3.35\ x\ 10^5\ J = (2\ kg)(897\ J/kg.K)(T-300\ K)\\\\5.38\ x\ 10^5\ J + 3.35\ x\ 10^5\ J = (1794 J/K)(T)\\\\T = \frac{8.73\ x\ 10^5\ J}{1794\ J/K}[/tex]
T = 486.6 K
