What is the value of the expression x^3y^2/6 + x^2y^2 x = -2 and y = 3?
A -45
B -30
С 24
D 27

[tex]\huge\text{Hey there!}[/tex]
[tex]\mathsf{\dfrac{(-2^3)(3^2)}{6}+(-2^2)(3^2)}[/tex]
[tex]\mathsf{(-2)^3=\bf -8}[/tex]
[tex]\mathsf{= \dfrac{-8(3^2)}{6}+(-2^2)(3^2)}[/tex]
[tex]\mathsf{3^2=\bf 9}[/tex]
[tex]\mathsf{= \dfrac{(-8)(9)}{6}+(-2^2)(3^2)}[/tex]
[tex]\mathsf{-8(9)= \bf -72}[/tex]
[tex]\mathsf{= \dfrac{-72}{6}+(-2^2)+(3^2)}[/tex]
[tex]\mathsf{\dfrac{-72}{6}=\bf -12}[/tex]
[tex]\mathsf{= -12+(-2)^2(3^2)}[/tex]
[tex]\mathsf{-2^2=\bf 4}[/tex]
[tex]\mathsf{= -12+4(3^2)}[/tex]
[tex]\mathsf{3^2=\bf 9}[/tex]
[tex]\mathsf{= -12+4(9)}[/tex]
[tex]\mathsf{4(9)= \bf 36}[/tex]
[tex]\mathsf{-12 + 36 = \bf 24}[/tex]
[tex]\boxed{\boxed{\large\text{Answer: \huge\bf Option C. 24}}}\huge\checkmark[/tex]
[tex]\text{Good luck on your assignment and enjoy your day!}[/tex]
~[tex]\frak{Amphitrite1040:)}[/tex]