Answer:
2 NaBr(aq) + Cl₂(g) ⇒ 2 NaCl(aq) + Br₂(l)
Explanation:
Let's consider the unbalanced equation that occurs when aqueous sodium bromide reacts with chlorine gas to form aqueous sodium chloride and liquid bromine. This is a single displacement reaction.
NaBr(aq) + Cl₂(g) ⇒ NaCl(aq) + Br₂(l)
We will start balancing Cl atoms by multiplying NaCl by 2.
NaBr(aq) + Cl₂(g) ⇒ 2 NaCl(aq) + Br₂(l)
Then, we get the balanced equation by multiplying NaBr by 2.
2 NaBr(aq) + Cl₂(g) ⇒ 2 NaCl(aq) + Br₂(l)
