Answer:
tan(E) =[tex]\sqrt{3\\}[/tex]
Step-by-step explanation:
Given: ED = 4[tex]\sqrt{6}[/tex] and CD = 6[tex]\sqrt{2\\}[/tex]
Step 1 : Find CE
ED² = CE² + CD²
(4√6)² = (CE)² + (6√2)²
96 = CE² + 72
24 = CE²
CE = 2√6
Step 2 : Find ∠E using side lengths
Based on our leg lengths : 6√2 & 2√6 , we can conclude that this is a
30-60-90 triangle (the sqaures are opposites yk)
Because 6√2 is the larger leg, and ∠E is opp side of CD,
∠E = 60
From there all you do is find the tangent with a calculator "tan(60)"
