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For the following exothermic reaction system at equilibrium:
H2O(g) CO(g) CO2(g) H2(g)
Choose the changes that will increase the value of K.
a. Decrease the volume (constant T)
b. Add H2O(g) (constant T)
c. Remove H2(g) (constant T)
d. Add a catalyst (constant T)
e. Add CO2(g) (constant T)
f. Increase the temperature
g. Decrease the temperature

Respuesta :

sebassandin

Answer:

See explanation.

Explanation:

Hello there!

In this case, for the chemical reaction:

[tex]H_2O(g) CO(g)\rightleftharpoons CO_2(g) H_2(g)[/tex]

It is widely known that the the only factor altering the equilibrium constant is the temperature because of its thermodynamic definition:

[tex]K=exp(-\frac{\Delta G(T)}{RT} )[/tex]

Which is temperature dependent on the denominator and on the Gibbs free energy of reaction. In such a way, the answers can be just f and g, as the other factors modify Q (reaction quotient) rather than K. Thus, we can discuss about f and g:

f. This would increase K if the Gibbs free energy of reaction is positive (nonspontaneous).

g. This would increase K if the Gibbs free energy of reaction is negative (spontaneous).

It is important to discuss those two because the Gibbs free energy is not given.

Regards!

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