Given:
The two points are (4,5) and (-3,-5).
To find:
The point-slope form equations could be produced with the given points.
Solution:
Slope formula:
[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]
The two points are (4,5) and (-3,-5). So, the slope of the line is:
[tex]m=\dfrac{-5-5}{-3-4}[/tex]
[tex]m=\dfrac{-10}{-7}[/tex]
[tex]m=\dfrac{10}{7}[/tex]
The point slope form of a line is:
[tex]y-y_1=m(x-x_1)[/tex]
Where, m is the slope of the line.
The slope of the line is [tex]m=\dfrac{10}{7}[/tex] is passes through the point (4,5). So, the point slope form is:
[tex]y-5=\dfrac{10}{7}(x-4)[/tex]
The slope of the line is [tex]m=\dfrac{10}{7}[/tex] is passes through the point (-3,-5). So, the point slope form is:
[tex]y-(-5)=\dfrac{10}{7}(x-(-3))[/tex]
[tex]y+5=\dfrac{10}{7}(x+3)[/tex]
Therefore, the point slope form of the given line is either [tex]y-5=\dfrac{10}{7}(x-4)[/tex] or [tex]y+5=\dfrac{10}{7}(x+3)[/tex].
