[tex]\huge\text{Hey there!}[/tex]
[tex]\mathsf{p^2 + 24 = 159}[/tex]
[tex]\large\text{SUBTRACT 24 to BOTH SIDES}[/tex]
[tex]\mathsf{p^2+24-24=159-24}[/tex]
[tex]\large\text{Cancel out: 24 - 24 because that gives you 0}[/tex]
[tex]\large\text{Keep: 159 - 24 because it helps you solve for p}[/tex]
[tex]\mathsf{159 - 24 = \bf 135}[/tex]
[tex]\large\text{New equation: }\mathsf{p^2 =135}[/tex]
[tex]\large\text{TAKE your SQUARE ROOT}[/tex]
[tex]\mathsf{p=\pm 3\sqrt{135}}[/tex]
[tex]\mathsf{\sqrt{135}=3\sqrt{15} \ OR\ -\sqrt{135} = -3\sqrt{15}}[/tex]
[tex]\large\text{Original answer: }\mathsf{\underline{p=3\sqrt{15}\ or\ p = -\sqrt{15}}}[/tex]
[tex]\boxed{\boxed{\large\text{Answer: \huge\bf D. 11.6}}}\huge\checkmark[/tex]
[tex]\text{Good luck on your assignment and enjoy your day!}[/tex]
~[tex]\frak{Amphitrite1040:)}[/tex]
