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Jen and her partner were assigned the Zn/Zn cathode/anode pair which they used to construct their electrolytic cell. They decided to keep the concentration of the corresponding Zn2+ solution constant at 1 M. If Jen ran her cell for 22.8 mins, what current (mA) did she use in order to transfer 9 x 10^-4 moles of electrons?

Respuesta :

ajeigbeibraheem

Answer:

63.2 mA

Explanation:

We all know that:

Current[tex]I = \dfrac{Q}{t}[/tex]

which can be further expressed as:

[tex]I = \dfrac{ne}{t}[/tex]

where;

n = number of electrons

e = charge on electrons

t = time (second)

Then; by replacing the values in the question, we have:

[tex]\dfrac{(9*10^{-4})\times6\times10^{23}\times1.6\times10^{-19}}{22.8\times60}[/tex]

[tex]= 0.06316 A \\ \\ \mathbf{I= 63.2 \ mA}[/tex]

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