Respuesta :
I (iodine)
Generally electron affinity increases from left to right across a period. Thus P (to the left of S in the same period) has a lower electron affinity thens S
And electron affinity decreases as you go down a group. Thus Se (below S in the same group) has a lower electron affinity then S.
Iodine, is in group 7A (or 17) which is to the right of group 6A (or 16), where sulfur lives). It has a higher electron affinity then S.
Google electron affinity for tables showing what an elements actualy affinity is.
Generally electron affinity increases from left to right across a period. Thus P (to the left of S in the same period) has a lower electron affinity thens S
And electron affinity decreases as you go down a group. Thus Se (below S in the same group) has a lower electron affinity then S.
Iodine, is in group 7A (or 17) which is to the right of group 6A (or 16), where sulfur lives). It has a higher electron affinity then S.
Google electron affinity for tables showing what an elements actualy affinity is.
Answer;
Iodine (I)
Explanation;
- The reactivity of elements increases with an increase in the electron affinity. Reactivity of non-metals relates well with the concept of electron affinity. The greater the tendency of attracting electrons the more reactive an element is.
- The electron affinity increases from left to right across a period and decreases down the groups of periodic table. This means phosphorus (P) and selenium (Se) have a lower electron affinity than sulfur, while Iodine has a higher electron affinity than sulfur and will thus greatly attract electrons from sulfur.