The mass of oxygen produced when 3.0 moles of potassium chlorate decomposed completely is 144 g
Equation for the reaction
We'll begin by writing the balanced equation for the reaction. This is given below:
2KClO₃ —> 2KCl + 3O₂
From the balanced equation above,
2 moles of KClO₃ decomposed to produce 3 moles of O₂.
How to determine the number of mole of oxygen produced.
From the balanced equation above,
2 moles of KClO₃ decomposed to produce 3 moles of O₂.
Therefore,
3 moles of KClO₃ will decompose to produce = (3 × 3) / 2 = 4.5 moles of O₂.
How to determine the mass of oxygen produced
- Molar mass of O₂ = 2 × 16 = 32 g/mol
- Mole of O₂ = 4.5 moles
- Mass of O₂ =?
Mass = mole × molar mass
Mass of O₂ = 4.5 × 32
Mass of O₂ = 144 g
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