The mass of NaHCO₃ needed to produce 2.659 moles of CO₂ is 446.712 g
We'll begin by writing the balanced equation for the reaction. This can be obtained as follow:
2NaHCO₃ —> Na₂CO₃ + CO₂ + H₂O
Molar mass of NaHCO₃ = 23 + 1 + 12 + (16×3)
= 84 g/mol
Mass of NaHCO₃ from the balanced equation = 2 × 84 = 168 g
From the balanced equation above,
168 g of NaHCO₃ decomposed to produce 1 mole of CO₂.
With the above information, we can obtain the mass of NaHCO₃ needed to produce 2.659 moles of CO₂. This can be obtained as follow:
From the balanced equation above,
168 g of NaHCO₃ decomposed to produce 1 mole of CO₂.
Therefore,
Xg of NaHCO₃ will decompose to produce 2.659 moles of CO₂ i.e
Xg of NaHCO₃ = 168 × 2.659
Xg of NaHCO₃ = 446.712 g
Thus, 446.712 g of NaHCO₃ is needed to produce 2.659 moles of CO₂.
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