Respuesta :

Space

Answer:

2900 g Au

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Chemistry

Atomic Structure

  • Reading a Periodic Table
  • Moles

Stoichiometry

  • Using Dimensional Analysis

Explanation:

Step 1: Define

[Given] 14.7 mol Au

[Solve] g Au

Step 2: Identify Conversion

[PT] Molar Mass of Au - 196.97 g/mol

Step 3: Convert

  1. [DA] Set up:                                                                                                     [tex]\displaystyle 14.7 \ mol \ Au(\frac{196.97 \ g \ Au}{1 \ mol \ Au})[/tex]
  2. [DA] Multiply [Cancel out units]:                                                                     [tex]\displaystyle 2895.46 \ g \ Au[/tex]

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

2895.46 g Au ≈ 2900 g Au

Otras preguntas