The center of a clock is at (0,0) in a coordinate system, and the minute hand is 10 inches long. Find the approximate coordinates of the tip of the minute hand at: 12:05 p.M.

Respuesta :

Answer:

(5, 8.66)

Step-by-step explanation:

Let x represent the x coordinate of the clock tip and y represent the y coordinate of the clock tip.

At 12:05 pm, the clock tip forms an angle of 60° with the x axis. Therefore:

θ = 60°

[tex]tan\theta=\frac{y}{x} \\\\tan60=\frac{y}{x} \\\\y=1.732x\\\\y-1.732x=0\ \ \ (1)[/tex]

Since the minute hand is 10 inches long, hence:

[tex]\sqrt{x^2+y^2}=10\\\\x^2+y^2=100\\\\substituting\ y=1.732x, gives\\\\x^2+(1.732x) ^2=100\\\\x^2+3x^2=100\\\\4x^2=100\\\\x^2=25\\\\x=5[/tex]

To find y, substitute x = 5:

y = 1.732(5) = 8.66

This means that the coordinate of the tip of the minute hand at: 12:05 p.M. is (5, 8.66)