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an ant crawls at a rate of 2 1/6 feet per minute at this rate how long does it take to end to call a distance of 5 1/5 ft enter your answer as a mixed number in simplest form ​

Respuesta :

durgasinha1

Step-by-step explanation:

Given :Ant crawls at the rate 2\frac{1}{6}

6

1

ft /min

=\frac{12+1}{6}

6

12+1

ft

=\frac{13}{6}

6

13

ft

Distance: 5\frac{1}{5}

5

1

ft

=\frac{25+1}{5}

5

25+1

ft

=\frac{26}{5}

5

26

ft

Time taken =\frac{Distance}{Speed}

Speed

Distance

=\frac{26/5}{13/6}

13/6

26/5

\frac{26*6}{5*13}

5∗13

26∗6

Dividing numerator and denominator by 13

=\frac{12}{5}

5

12

=2\frac{2}{5}

5

2

min

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