What is the area of the following trapezoid in square feet?
A-B:
135 ft2
165 ft2
82.5 ft2
64.9 ft2

Answer:
82.5 ft²
Step-by-step explanation:
The area (A) of a trapezoid is calculated as
A = [tex]\frac{1}{2}[/tex] h (b₁ + b₂)
where h is the perpendicular height and b₁, b₂ the parallel bases
Here h = 7.5, b₁ = 7 and b₂ = 15 , then
A = [tex]\frac{1}{2}[/tex] × 7.5 × (7 + 15) = 0.5 × 7.5 × 22 = 82.5 ft²
Answer:
135 ft^2 (first answer choice)
Step-by-step explanation:
Convert the length of the 7 yd base to feet: 21 ft.
Then the average length of the trapezoid is (15 ft + 21 ft)/2 = 36/2 ft = 18 ft.
The area of the trapezoid is then (average length)(height), or
A = (18 ft)(7.5 ft) = 135 ft^2 (first answer choice)