Answer:
20.00 thousand cell
Step-by-step explanation:
The problem can be solved using integration
[tex]\begin{aligned} r &=4+\int_{0}^{3} 8 e^{0.18 t} d t \\ &=4+3 \cdot\left[\frac{e^{0.18t}}{0.18}\right]_{0}^{3} \\ &=4+\frac{3}{0.18}\left(e^{0.18(3)}-e^{0.18(0)}\right) \\ &=19.9996 \end{aligned}[/tex]
[tex]\approx 20.00[/tex] thousand cells
the correct answer upto 2 decimal place.
