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Kalyan Singhal Corp. makes three products, and it has three machines available as resources as given in the following LP problem:

Maximize contribution = 5X1 + 4X2 + 3X3
Subject to: 1X1 + 7X2 + 4X3 <= 90 (hours on machine 1)

2X1 + 1X2 + 7X3 <= 96 (hours on machine 2)
8X1 + 4X2 + 1X3 <= 90 (hours on machine 3)
X1, X2, X3 >=0

Determine the optimal solution using LP software. the optimal achieved is

X1=
X2=
X3=

Respuesta :

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Answer:

Step-by-step explanation:

[tex]\text{Maximize p = 5X1 + 4X2 + 3X3 subject to;} \\ \\ 1X1 + 7X2 + 4X3 <= 90[/tex]

[tex]2X1 + 1X2 + 7X3 <= 96[/tex]

[tex]8X1 + 4X2 + 1X3 <= 90[/tex]

[tex]X1 > = 0[/tex]

[tex]X2 >= 0[/tex]

[tex]X3 >=0[/tex]

[tex]\text{USing LP software, The Optimal Solution: Maximum Contribution} = 90.547;}\\ \\ x1 = 7.07692, \\ \\ x2 = 5.62393, \\ \\ x3 = 10.8889[/tex]

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