Answer:
The temperature is "298.51 K".
Explanation:
The given values are:
Density of ammonia,
d = 0.812 g/L
Pressure,
P = 1.17 atm
Mass:
M = [tex]NH_3[/tex]
= [tex]14+ 1\times 3[/tex]
= [tex]17[/tex]
As we know,
⇒ [tex]PV=nRT[/tex]
∴ [tex]T=\frac{PV}{nR}[/tex]
[tex]=\frac{PV}{\frac{W}{M}\times R }[/tex]
[tex]=\frac{PVM}{W\times R}[/tex]
By putting the value of "W", get
[tex]=\frac{PVM}{V\times d\times R}[/tex]
[tex]=\frac{P\times M}{d\times R}[/tex]
On substituting the values in the above equation, we get
[tex]=\frac{1.17\times 17}{0.812\times 0.08205}[/tex]
[tex]=\frac{19.89}{0.06699}[/tex]
[tex]=298.51 \ K[/tex]
