Answer:
Explanation:
From this question, we are to fill in the blanks with the appropriate correct answers.
[tex]\text{The reason for the trend in the previous question is because Bromine is } \mathbf{withdrawing}[/tex][tex]\text{electron density from the carbon the proton is on, resulting in the proton being }\mathbf{deshielded, }[/tex][tex]\text{thus the proton nuclei is} \ \ \mathbf{more} \ \ \text{effected by the applied magnetic field leading to a }[/tex]
[tex]\text{greater difference in energy of the nuclei's spin states.}[/tex]
NOTE: that the electron-withdrawing groups decrease the electron density around the proton nucleus and therefore the nucleus feels the external magnetic field more. Hence, it requires a larger frequency to attain resonance(downfield).
