The equation of the line that passes through P and is perpendicular to PQ is y=-1/3x+12.
Given that, the line PQ has equation y = 3x - 8 and point P has coordinates (6, 10).
We need to find the equation of the line that passes through P.
What is the condition of slope for perpendicular lines?
The slopes of two perpendicular lines are negative reciprocals of each other. This means that if a line is perpendicular to a line that has a slope of m, then the slope of the line is -1/m.
Here, the slope of the equation is 3.
The equation of the line that passes through P and is perpendicular to PQ is -1/3.
Now, 10=-1/3(6)+c
⇒c=12
Thus, y=-1/3x+12
Therefore, the equation of the line that passes through P and is perpendicular to PQ is y=-1/3x+12.
To learn more about the equation of the line visit:
https://brainly.com/question/21511618.
#SPJ2
