find angle sqr and pqr

Answer:
The answer is number C
Step-by-step explanation:
[tex](2x + 6) + (10x - 5) = 61 \\ 12x + 1 = 61 \\ 12x = 60 \\ x = 5 \\ then \\ m < sqr = 2 \times 5 + 6 = 16 \\ m < pqr = 10 \times 5 - 5 = 45[/tex]
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