YourAverageFangirl
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What happens to the function f(x)=(x−1)2+1 when it becomes f′(x)=(13x−1)2+1?
It is compressed toward the y-axis.
It is stretched away from the x-axis.
It is compressed toward the x-axis.
It is stretched away from the y-axis.

Respuesta :

I think the answer is the last one

     Option (2). function f will be stretched away from the x-axis to form the image function f'.

Rule for the transformation of a function:

  •  For a function is given by,

          f(x) = a(x - h)² + k

          If a > 1, graph of the function will be stretched vertically (towards  

          y-axis or away from the x-axis).

          If 0 < a < 1, graph of the function will be compressed vertically

          (towards x-axis or away from the y-axis)

Function given in the question,

f(x) = (x - 1)² + 1

Transformed function → f'(x) = (13x - 1)² + 1

                                        [tex]f'(x)=13(x-\frac{1}{13})^2+1[/tex]

By applying rule of the transformation,

a = 13 and 13 > 1

Therefore, function will be stretched vertically away from the x-axis.

      Hence, Option (2) will be the answer.

Learn more about the transformations here,

https://brainly.com/question/19279703

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