Answer:
Maximum height = 346 feet
Step-by-step explanation:
Given that,
The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation as follows :
[tex]y = -16x^2 + 136x + 57[/tex] .....(1)
We need to find the maximum height reached by the rocket. For maximum height,
Put dy/dt = 0
So,
[tex]\dfrac{d}{dt}( -16x^2 + 136x + 57)=0\\\\-32x+136=0\\\\x=\dfrac{136}{32}\\\\x=4.25[/tex]
No, put x = 4.25 in equation (1).
[tex]y = -16(4.25)^2 + 136(4.25)+ 57\\\\y=346\ feet[/tex]
So, the maximum height reached by the rocket is equal to 346 feet.
