Answer:
18 litres
Explanation:
Using Boyle's law equation as follows:
P1V1 = P2V2
Where;
P1 = initial pressure (atm)
P2 = final pressure (atm)
V1 = initial volume (litres)
V2 = final volume (litres)
According to the information in this question, An inflated basketball hold 6 liters (V1) of air at 3 atm (P1). The volume of air (V2) at 1 atm (P2) that went into the ball can be calculated thus:
Using P1V1 = P2V2
3 × 6 = 1 × V2
18 = V2
V2 = 18 litres.
