Answer: The concentration of the solution is 0.18 M
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.
[tex]Molarity=\frac{n}{V_s}[/tex]
where,
n = moles of solute
[tex]V_s[/tex] = volume of solution in L
moles of [tex]CaCl_2[/tex] = [tex]\frac{\text {given mass}}{\text {Molar mass}}=\frac{220g}{111g/mol}=1.98mol[/tex]
Now put all the given values in the formula of molality, we get
[tex]Molarity=\frac{1.98mol}{11L}=0.18M[/tex]
Therefore, the concentration of the solution is 0.18 M
