Answer:
a) 0.5 = 50% of flanges exceed 1 millimeter.
b) A thickness of 0.96 millimeters is exceeded by 90% of the flanges
Step-by-step explanation:
A distribution is called uniform if each outcome has the same probability of happening.
The uniform distributon has two bounds, a and b, and the probability of finding a value higher than x is given by:
[tex]P(X > x) = \frac{b - x}{b - a}[/tex]
The thickness of a flange on an aircraft component is uniformly distributed between 0.95 and 1.05 millimeters.
This means that [tex]a = 0.95, b = 1.05[/tex]
(a) Determine the proportion of flanges that exceeds 1.00 millimeters.
[tex]P(X > 1) = \frac{1.05 - 1}{1.05 - 0.95} = \frac{0.05}{0.1} = 0.5[/tex]
0.5 = 50% of flanges exceed 1 millimeter.
(b) What thickness is exceeded by 90% of the flanges?
This is x for which:
[tex]P(X > x) = 0.9[/tex]
So
[tex]\frac{1.05 - x}{1.05 - 0.95} = 0.9[/tex]
[tex]1.05 - x = 0.9*0.1[/tex]
[tex]x = 1.05 - 0.9*0.1[/tex]
[tex]x = 0.96[/tex]
A thickness of 0.96 millimeters is exceeded by 90% of the flanges
