Answer:
ΔE = h f
Explanation:
The energy for a quantum harmonic oscillator is given by the expression
E = (ν + ½) h f
where ν is an integer and ½ is the ground state energy and zero point,
In this case, if the emission frequency is f, the position between the initial (excited) and final (ground state) states is
DE = (v_f- v₀) hf
the minimum emitted frequency is
v_f = 1
v₀ = 0
ΔE = h f
