contestada

A friend of yours has climbed to the top of the Empire State building. You would ask him why he didn’t just take the elevator, but he is too far away for that. Clinging to the radio antenna on the top, he is now 1,250 feet. In the air. From this vantage point, he tosses a paper airplane. The airplane glides towards The earth at a peaceful angle of 15 degrees. How far did the airplane travel from the base of the building? Make sure your friend uses the elevator next time by showing your work!

(Will mark brainliest)

A friend of yours has climbed to the top of the Empire State building You would ask him why he didnt just take the elevator but he is too far away for that Clin class=

Respuesta :

Answer:

C. Cos(15) = 1250/x

Step-by-step explanation:

The angle at the top of the building is the peaceful angle of 15 degrees.

You need to work out the length that goes downwards from the top of the building, which is the hypotenuse.

You have been given 1,250 feet, which is the vertical length, also the adjacent side.

15 = Angle next to the adjacent side given and the angle at which the airplane flew

1250 = Adjacent, also the height that your friend reached.

x = Hypotenuse

Cos(x) = Adjacent/Hypotenuse

Therefore the answer would be C. Cos(15) = 1250/x

I hope the explanation helps you.