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15 POINTS PLEASE HELP!!

Quadrilateral ABCD with vertices A(-1, 0), B(3, 3), C(6, -1) and D(x, -y). If vertices ABCD forms a square, find the length of diagonal BD. Round your answer to the nearest hundredth.

Respuesta :

Answer:

7.07

Step-by-step explanation:

Find vertices D with desmos (it's 2,-4).

Use the distance formula or diagonal=a√2 (d=5√2)

Multiply them and get 7.07.

Since the vertices forms a square, all sides are the same length which is 5.

Also you bca kid rt?