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How many grams of nitrogen dioxide are required to produce 260 grams of nitrogen monoxide? 3NO2 + H20 → 2HNO3 + NO

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menan

Answer:

1196 g

Explanation:

N= 14 O= 16

every 3 moles of NO2 gives one mole of NO

So, 3[14 + (2×16)] = 138 grams of NO2

gives : 14+16 = 30 grams of NO

NO2 NO

138 30

? 260

Therefore, 260 × 138 ÷ 30 = 1196 g of NO2 are required

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