Seventy pupils (37 boys and 33 girls) are divided into two groups, with forty pupils in Group I and thirty pupils in Group II. How many more boys are there in Group I than there are girls in Group II?

Respuesta :

Answer:

7 more boys

Step-by-step explanation:

Given

[tex]Total = 70[/tex]

[tex]Boys = 37[/tex]

[tex]Girls = 33[/tex]

[tex]Group\ 1 = 40[/tex]

[tex]Group\ 2 = 30[/tex]

Required

Number of more boys than girls in group 2

Represent the number of boys in group 1 with B and the number of girls with G.

So:

[tex]B + G = 40[/tex]

Make G the subject

[tex]G = 40 - B[/tex]

The number of girls in group 2 will be:

Total number of girls (33) - number of girls in group 1(40 - B)

So, we have:

[tex]Group\ B\ Girls = 33 -(40 - B)[/tex]

[tex]Group\ B\ Girls = 33 -40 + B[/tex]

[tex]Group\ B\ Girls = -7 + B[/tex]

[tex]Group\ B\ Girls = B-7[/tex]

This means that there are 7 more boys than girls