Answer:
∠ABC = 94°
∠BCD = 25°
∠ACB = 43°
Step-by-step explanation:
∠ABD = 133°
Since △ADC is an isosceles triangle where AD = CD, it means that ∠CBD = 133°
We know sum of angles at a point is 360°.
Thus; ∠ABC = 360 - (133 + 133)
∠ABC = 94°
Now, in △BCD, ∠B = 133° and ∠D = 22°
Sum of angles in a triangle = 180°
Thus; ∠BCD = 180 - (133 + 22)
∠BCD = 25°
Since the △ABC is also an isosceles triangle , it means that;
In △ABC, ∠A = ∠C
Thus; ∠ACB = (180 - 94)/2
∠ACB = 86/2
∠ACB = 43°
