If AC is the perpendicular bisector of BD and BD is the perpendicular bisector of AC, then how is triangle APB congruent to triangle CPB?

Answer:
AB=BC
4X-1=1+2x so x=1 and both sides are 3
Step-by-step explanation:
since bd is a perpendicular bisector the two triangles formed are congruent so AB=BC
4X-1=1+2x so x=1 and both sides are 3