Answer:
a) y = y₀ - 4.9, v = -9.8 m / s, b) y =y₀ - 19.6, v = - 19 m / s
c) y =y₀ - 44.1, v = - 29.4 m / s
Explanation:
To solve this exercise let us use the kinematic relations
y =y₀ + v₀ t - ½ g t²
v = v₀ - g t
They indicate that the body is released therefore the initial velocity is zero v₀ = 0
y = y₀ - ½ g t²
v = - gt
a) the position and velocity for t = 1s
y = y₀ - ½ 9.8 12
y = y₀ - 4.9
v = - 9.8 1
v = -9.8 m / s
the negative sign indicates that the velocity is directed downwards
b) t = 2 s
y =y₀ - ½ 9.8 2 2
y =y₀ - 19.6
v = - 9.8 2
v = - 19 m / s
c) t = 3 s
y = y₀ - ½ 9.8 3 2
y =y₀ - 44.1
v = - 9.8 3
v = - 29.4 m / s
