Answer:
84 g of N₂
Explanation:
We begin from the reaction:
N₂O₄ + 2N₂H₄ → 3N₂ + 4H₂O
1st step: Find out the limiting reactant.
We convert the mass to moles.
276 g . 1mol/ 92g = 3 moles of N₂O₄
64 g . 1mol / 32g = 2 moles of hidrazine
Limiting reactant is the hydrazine. Ratio is 1:2, then for 3 moles of tetroixde I may need 6 moles of N₂H₄. (But I only have 2).
To determine the grams of produced nitrogen we see stoichiometry (2:3)
2 moles of hydrazine can produce 3 moles of N₂
Definetaly our 2 moles make 3 moles of gas.
We convert the moles to mass.
3 mol . 28g /1mol = 84 g of N₂
