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Selina drops a golf ball down a deep well. The ball falls with only the force of gravity acting on it (assume no air resistance).
Figure 4-2A
What will be the velocity of the ball be 3 seconds after it has been dropped?

Respuesta :

Let’s make a list of variables:
x = ?
t = 3 s
Vi = 0 (it is released from rest)
Vf = ? (This is what we’re finding)
a = -9.81 m/s^2
(Note I am assuming that the negative direction is down, hence the negative acceleration)
Apply the appropriate kinematic equation:
Vf = Vi + at
Vf = 0 + (-9.81)(3)
Vf = -29.43 m/s

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