Solve for x to the nearest tenth.
please help i’m failing

Answer:
x≈ 8.3
Step-by-step explanation:
ok first you have to find the hypotenuse of the smaller triangle
a²+b²=c²
2²+4²=c²
4+16=20
√20≈ 4.5
4.5²+7²=c²
20.25+49≈ 69.25
√69.25≈ 8.3
Answer:
x = [tex]\sqrt{69}[/tex]
Step-by-step explanation:
Pythagorean theorem: A^2 + B^2 = C^2
first, find the length of the line cutting through the shape:
let's call this line L.
plug the numbers into the theorem.
4^2 + 2^2 = L^2
16 + 4 = L^2
20 = L^2
next, plug 7 and L into the theorem again to find x
L^2 + 7^2 = x^2
20 + 49 = x^2
69 = x ^2
x = [tex]\sqrt{69}[/tex]