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How many milliliters of 0.188 M HClO 4 solution are needed to neutralize 50.00 mL of 0.0789 M NaOH?
a) 119
b) 0.742
c) 21.0
d) 0.0477
e) 8.39x10^-3

Respuesta :

119 so a I think that's Is me anser

The volume of space it takes up, whereas its mass is the amount of matter it contains. A sample's density is the quantity of mass per unit of volume.

Equation:

[tex]HClO_4 +NaOH \longrightarrow NaClO_4 + H_2O\\\\[/tex]

HClO₄ is a monoprotic strong acid.

1 mol of HClO₄ reacts with 1 mol of NaOH for neutralization.

Calculating the moles of NaOH [tex]= (0.0789\ M) \times (0.050\ L) = 0.003945\ mol[/tex]

Calculating the needed moles in HClO₄ [tex]= 0.003945 \ mol[/tex]

Calculating the HClO₄ Molarity that is 0.188 M

Calculating the HClO₄ volume that is needed [tex]= \frac{(0.003945\ mol) }{ (0.188\ M)} = 0.020\ L[/tex]

Therefore, the volume of HClO₄ that is needed = 20 mL

Find out more about the Stoichiometry here:

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