Respuesta :
Answer:
0,1276 M
Explanation:
Molair mass of NaOCl = 74,44 g/mol
You have 9,5 g/L.
You need to calculate with the molair mass, how many moles 9,5 g are:
9,5 g / 74,44 g/mol = 0,1276 mol
0,1276 mol / 1 L = 0,1276 M
The molarity of a bleach solution containing 9.5 g of NaOCL per liter of bleach is mathematically given as
M= 0.1276 M
What is the molarity of a bleach solution containing 9.5 g of NaOCL per liter of bleach?
Generally, the equation for the Molar mass is mathematically given as
M=m/(g/mol)
Therefore
M=9,5 g / 74,44 g/mol
M= 0,1276 mol
Hence
M= 0.1276 M
In conclusion, the molarity
M= 0.1276 M
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