Pls help this is my last problem and I need to pass this class?!?

Answer:
A = 50°
Step-by-step explanation:
[tex](2x - 10) + (x + 30) + 70 = 180 \\ 2x + x = 180 + 10 - 30 - 70 \\ 3x = 90 \\ x = \frac{90}{3} \\ x = 30[/tex]
Then
[tex]a = 2x - 10 \\ a = 2(30) - 10 \\ a = 60 - 10 \\ a = 50[/tex]
[tex]\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}[/tex]
Actually Welcome to the Concept of the Triangles.
Since we know that, the Angle sum property of a triangle is equal to 180°.
means that, <A + <B + <C = 180°
so we can write as,
==> 2x-10 + x + 30 +70 = 180°
===>3x +90 = 180
==> 3x = 90
hence, x = 30°
so now, substitute angle x,
So angle A is => 2(30)-10 => 60-10 = 50°
hence Angle A = 50°.