Given a term in an arithmetic sequence and
the common difference find the 100th term.


a14= 102
d = 10


Please help, i’m struggling.

Respuesta :

Answer:

100th term = 962

Step-by-step explanation:

You need  to find the first term of the sequence

The formula to use is

[tex]a_{n} = a_{1} + (n - 1)d[/tex]    In your problem, n = 14.  So,

[tex]102 = a_{1} + (14 - 1)10\\102 = a_{1} + 130\\a_{1} = -28\\\\[/tex]

Now you can find the 100th term.  n = 100, first term = -28 and d = 10

[tex]a_{100} = -28 + (100 - 1)10\\ = -28 + 990\\ = 962[/tex]

100th term = 962