PLEASE HELP
WITH THESE TWO QUESTIONS! IF I DONT HAVE THEM DONE IN THE NEXT HOUR IM SCREWED. ILL GIVE BRAINLIEST TO THE PERSON WHO SHOWS THE WORK. (Its the top two questions)

1. First you have to find the area of the trapezoid using the formula (a+b)h/2 where a= 10, b=15, and h=8. The answer will be 100. Then subtract the area of the square inside, which is 35. The final answer is 65.

2. Subtract from the dimensions of the landscape to find the dimensions of the patio. The length of the patio is 11 ft and the width is 5 ft. Therefore, the area is 55 ft^2

94639 94639 · Answer 2 · 2021-02-19T19:27:12+01:00

Answer:

Alright, helping you because I feel bad. 1) 76 in. 2) 24 in.

Step-by-step explanation:

1. [tex]A= \frac{a+b}{2} h[/tex] a= base b= base h= height Plug in the numbers, [tex](\frac{10+15}{2} ) 8= 100[/tex], but we still need to subtract the area of the un-shaded region (5×2)+(7×2)= 24

100-24= 76

2. Find the area of both landscaping rectangles, including the patio bit.

(14×2)+(8×2)=

28+16=

44in. The two rectangles are the same size, so they both have an equal area. Now we find the area of just the patio spot, W= (8-3)×2 L= (14-3)×2 W= 10 L= 22 A=32 in.

Now, we multiply by two, since we counted it twice, 64 in.

Finally, subtract 64 from the the sum of the two areas from the landscape rectangles, 88-64= 24 in.

PLEASE HELP WITH THESE TWO QUESTIONS! IF I DONT HAVE THEM DONE IN THE NEXT HOUR IM SCREWED. ILL GIVE BRAINLIEST TO THE PERSON WHO SHOWS THE WORK. (Its the top two questions)

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PLEASE HELP
WITH THESE TWO QUESTIONS! IF I DONT HAVE THEM DONE IN THE NEXT HOUR IM SCREWED. ILL GIVE BRAINLIEST TO THE PERSON WHO SHOWS THE WORK. (Its the top two questions)