Answer:
If nitrogen = 30.4% then oxygen = 100-30.4 = 69.6%
divide each % value by atomic mass
N = 30.4/14 = 2.17
O = 69.6/16 = 4.35
Divide each y smaller:
N = 2.17/2.17 = 1
O = 4.35/2.17 = 2
Explanation:
"The empirical Formula will be [tex]NO_{2}[/tex]."
What is empirical formula?
In chemistry, an empirical formula is the simplest thought of the entire number quantity of atoms in a molecule.
It is given that N = 30.4%.
The % of O can be determined as: 100-30.4%= 69.65.
Now, after dividing % value with atomic mass, we get.
Mass of N= 14 and Mass of O = 16.
N= 30.4/14= 2.17
O = 69.6/ 16= 4.35
It can be seen that N has less number as compared to O . So, divide each with 2.17.
N= 2.17/2.17 = 1
O = 4.35/2.17=2
So the empirical formula will be [tex]NO_{2}[/tex].
To know more about empirical formula click here.
https://brainly.com/question/21280037.
#SPJ2
