In the somewhat less than towering ski slopes of northeastern Iowa new skiers come to learn to ski. On Big Bunny Slope skiers will fail to make the turn at Big Bend. On Little Bunny Slope, skiers will sometimes tumble at Little Hill. The ski instructors send the new skiers down the two slopes in groups of 30, wait a few moments, and then send the Ski Patrol Ambulance down after them, stopping at Big Bend and then Little Hill. The skiers descend the slopes far enough apart that they don't run into each other, so their spills are all independent.

Required:
a. The probability that a random new skier in the group will need to be carried to the First Aid Station after a spill at Big Bend is 0.35. If we define the random variable B = number of new skiers needing to be driven to the First Aid Station from Big
Bend, we can model this situation as a binomial chance experiment. What is the mean and standard deviation of B?
b. The probability that a random new skier in the group will need to be carried to the First Aid Station after a spill at Little Hill is 0.15. If we define the random variable L = number of new skiers needing to be driven to the First Aid Station from Little Hill, what is the mean and standard deviation of L?

Respuesta :

Answer:

A. Mean = 10.5, standard deviation = 2.61247

B. Mean = 4.5, stand deviation = 1.955761

Step-by-step explanation:

Number in a group = 30

So n= 30

A.

It follows the binomial distribution

n = 30, probability p = 0.35

The mean = n*p

= 30x0.35

= 10.5

The standard deviation = √np(1-p)

= √10.5(1-0.35)

= √10.5(0.65)

= √6.825

= 2.61247

B. Probability of a new skier carried = 0.15

n = 30

Mean = n*p

= 30x0.15

= 4.5

The standard deviation = √np(1-p)

= √4.5(1-0.15)

= √4.5(0.85)

= √3.825

= 1.955761