Respuesta :
Answer: The mass of [tex]CO_2[/tex] and [tex]H_2O[/tex] produced are 336.6 g and 183.6 g respectively.
Explanation:
The combustion reaction between propane and oxygen leads to formation of carbon dioxide and water.
Law of Conservation of mass states that the mass will remain constant for a balanced equation. This is carried out when the total number of atoms on reactant side is same as the total number of atoms on the product side. Thus the equation must be balanced.
[tex]C_3H_8+5O_2\rightarrow 3CO_2+4H_2O[/tex]
a) 1 mol of propane produces = 3 moles of [tex]CO_2[/tex]
Thus 2.55 mol of propane produces = [tex]\frac{3}{1}\times 2.55=7.65 moles of [tex]CO_2[/tex]
mass of [tex]CO_2=moles\times {\text {molar mass}}=7.65mol\times 44g/mol=336.6g[/tex]
b) 1 mol of propane produces = 4 moles of [tex]H_2O[/tex]
Thus 2.55 mol of propane produces = [tex]\frac{4}{1}\times 2.55=10.2 moles of [tex]H_2O[/tex]
mass of [tex]H_2O=moles\times {\text {molar mass}}=10.2mol\times 18g/mol=183.6g[/tex]
The mass of [tex]CO_2[/tex] and [tex]H_2O[/tex] produced are 336.6 g and 183.6 g respectively.
