Respuesta :

sebassandin

Answer:

[tex]V_2=120L[/tex]

Explanation:

Hello!

In this case, since Helium is undergoing a volume-pressure change, according the Boyle's law, we infer the following equation is used:

[tex]P_1V_1=P_2V_2[/tex]

Thus, since we are not given the volume at 0.25 atm, we can solve for V2 to do so:

[tex]V_2=\frac{P_1V_1}{P_2}[/tex]

Thus, we plug in to obtain:

[tex]V_2=\frac{1atm*30L}{0.25atm}=120L[/tex]

Best regards!

onyebuchinnaji

The final volume of the balloon at the given altitude is 120 L.

The given parameters;

  • initial volume of the balloon, V₁ = 30 L
  • initial pressure, P₁ = 1 atm
  • final pressure of the balloon, P₂ = 0.25 atm

The final volume of the balloon at the given altitude is calculated by applying Boyles law as follows;

[tex]P_1 V_1 = P_2 V_2\\\\V_2 = \frac{P_1V_1}{P_2} \\\\V_2 = \frac{30 \times 1 }{0.25} \\\\V_2 = 120 \ L[/tex]

Thus, the final volume of the balloon at the given altitude is 120 L.

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