Answer:
[tex]\boxed {\boxed {\sf 301.325 \ Joules }}[/tex]
Explanation:
Since we are given the mass, specific heat, and change in temperature, we should use this formula for energy:
[tex]q=mc \Delta T[/tex]
The mass of the graphite is 25 grams. Graphite's specific heat is 0.709 J/g °C. The change in temperature is 17 degrees Celsius.
[tex]m= 25 \ g \\c= 0.709 \ J/g \ \textdegree C \\\Delta T= 17 \ \textdegree C[/tex]
Substitute the values into the formula.
[tex]q= (25 \ g)( 0.709 \ J/g \ \textdegree C )( 17 \ \textdegree C)[/tex]
Multiply the first two numbers. The grams will cancel.
[tex]q= 17.725 \ J/ \textdegree C(17 \ \textdegree C)[/tex]
Multiply again. This time the degrees Celsius cancel.
[tex]q= 301.325 \ J[/tex]
The graphite loses 301.325 Joules of energy.
