onsider the iodination of salicylamide by sodium iodide and sodium hypochlorite via an electrophilic aromatic substitution to form iodo-salicylamide. Reaction scheme illustrating the iodination of salicylamide by sodium iodide and sodium hypochlorite via an electrophilic aromatic substitution to form iodo-salicylamide. Calculate the molar masses of the reactants and product. Report molar masses to 1 decimal place.

Respuesta :

Answer:

The answer is "[tex]\bold{263 \ and \ 137.1 \frac{g}{ mol}}[/tex]".  

Explanation:

The chemical formula for Salicylamide: [tex]C_7H_7NO_2[/tex]

[tex]\to (12.011 \ \frac{g}{mol} \times 7)+(1.008 \ \frac{g}{mol} \times 7)+(14.0067 \frac{g}{mol} \times 1)+(15.999 \frac{g}{mol} \times 2) \\\\\to (84.077 \ \frac{g}{mol} )+(7.056 \ \frac{g}{mol} )+(14.0067 \frac{g}{mol})+(31.998 \frac{g}{mol} ) \\\\\to (84.077 \ \frac{g}{mol} )+(7.056 \ \frac{g}{mol} )+(14.0067 \frac{g}{mol})+(31.998 \frac{g}{mol} ) \\\\ =137.1377 \approx 137.1\ \frac{g}{mol}[/tex]

The chemical formula of Iodosalicylamide:[tex]C_7H_6INO_2[/tex]

[tex]\to (12.011\frac{g}{mol}\times 7)+(1.008\frac{g}{mol}\times 6)+(126.904\frac{g}{mol}\times 1)+(14.0067\frac{g}{mol}\times 1)+(15.999\frac{g}{mol}\times 2) \\\\\to (84.077\frac{g}{mol})+(6.048\frac{g}{mol})+(126.904\frac{g}{mol})+(14.0067\frac{g}{mol})+(31.998\frac{g}{mol}) \\\\=263.0337 \approx 263.0\ \frac{g}{mol}[/tex]