Respuesta :
Answer:
a) dull, orange, bitter ----> 3/16 D- Oo Bb
b) glossy, cream, nonbitter ---> 1/16 dd oo bb
c) heterozygous for all 3 genes ---> 2/16 Dd Oo Bb
Explanation:
Available data:
- dull fruit (D-) is dominant to glossy fruit (dd)
- orange fruit color (O-) is dominant to cream fruit color (oo)
- bitter cotyledons (B-) are dominant to non-bitter cotyledons (bb)
- Cross: a plant heterozygous for all 3 genes with a plant that is heterozygous for dull fruit but has cream fruit color and non-bitter cotyledons.
Parentals) Dd Oo Bb x Dd oo bb
To get the proportions of the offspring using the forked-line method, we must analyze each gene separately.
D gene:
Parentals) Dd x Dd
Gametes ) D d D d
Punnett square) D d
D DD Dd
d dD dd
F1) 1/4 DD
2/4 Dd
1/4 dd
O gene:
Parentals) Oo x oo
Gametes) O o o o
Punnett square) O o
o Oo oo
o Oo oo
F1) 1/2 Oo
1/2 oo
B gene:
Parentals) Bb x bb
Gametes) B b b b
Punnett square) B b
b Bb bb
b Bb bb
F1) 1/2 Bb
1/2 bb
What proportion of the offspring will be
a) dull, orange, bitter
(1/4 DD + 2/4 Dd) x 1/2 Oo x 1/2 Bb = 3/4 D- x 1/2 Oo x 1/2 Bb
3/16 D- Oo Bb
b) glossy, cream, nonbitter
1/4 dd x 1/2 oo x 1/2 bb
1/16 dd oo bb
c) heterozygous for all 3 genes
2/4 Dd x 1/2 Oo x 1/2 Bb
2/16 Dd Oo Bb